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Aleksandr-060686 [28]
3 years ago
11

Temperature at 9:00PM was 15° By 5 AM the temperature had dropped 20° what was the temperature at 5 PM

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
From 9 P.M. to 5 A.M. the temperature dropped 20°, making the rate over 8 hours, -2.5° Per Hour. By 5 A.M., the temperature is -5° since we had to do 15 - 20. From 5 AM to 5 P.M. is 12 hours so -2.5 x 12 = -30 making 30 how much the temperature dropped between 5 A.M. to 5 P.M. Finally, our last equation is -5 - 30 making -35 our answer.
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Step-by-step explanation:

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Which is the simplified form of the expression (6 to the power of -2 times 6 to the power of 5) to the -3rd power?
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Step-by-step explanation:

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2 years ago
in triangle PQR the measure of angle R=90, QP=73, RQ=55, and PR=48. what is the value of the sine of angle P to the nearest Hund
alexandr402 [8]

Answer:

P ≈ 48.89°(nearest hundredth)

Step-by-step explanation:

The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.

Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.

opposite side(QR) = 55

adjacent side(PR) = 48

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sin P = opposite/hypotenuse

sin P = 55/73

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P = sin⁻¹ 0.75342465753

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3 years ago
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