D is the answer to your question
Answer:
4
Step-by-step explanation:
Question:
Ryan will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $57.98 and costs an additional $0.14 per mile driven. The second plan has an initial fee of 53.98 and costs an additional $0.16 per mile driven. How many miles would Ryan need to drive for the two plans to cost the same?
Answer:
The number of miles Ryan needs to drive for the two plans to cost the same is 200 miles
Step-by-step explanation:
Here we have
The initial fee of the first plan = $57.98
Additional mile cost of the first plan = $0.14
The initial fee of the second plan = $53.98
Additional mile cost of the first plan = $0.16
Let the mileage required for the two plans to cost the same be Y miles
Therefore,
$57.98 + $0.14 ×Y = $53.98 + $0.16 ×Y
$0.16 ×Y - $0.14 ×Y = $57.98 - $53.98 = $4.00
$0.02 ×Y = $4.00
Y = 200 miles
The number of miles driven for the two plans to cost the same = 200 miles.
A because it can be rearranged to the y = mx + c format. y = -1/40 x + 4
Answer:
Red:green = 3:1, not 3:2
r:g = 3:1, so g:r = 1:3 = 2:6
r:t = 2:11 = 6:33
g:r:t = 2:6:33
now just read off the ratios.
r:t = 6:33 = 2/11
b:t = 1 - (g:t - r:t) = 25/33
b:g = 25/2
r:b = 6/25
Step-by-step explanation:
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