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Papessa [141]
2 years ago
5

Solve each word problem by setting up a system of equations.

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
6 0
X=2x(2y+3x) numbers
You might be interested in
Please help!<br><br> 7|-7x-3|=21
arlik [135]

Divide by 7.

... |-7x -3| = 3

Unfold to two equations.

... -3 = -7x -3 . . . . . the content of the absolute value is negative

... 0 = -7x . . . . . . . . add 3

... 0 = x . . . . . . . . . . divide by -7

and

... 3 = -7x -3 . . . . . . the content of the absolute value is positive

... 6 = -7x . . . . . . . . add 3

... -6/7 = x . . . . . . . . divide by -7

The solutions are ...

... x = -6/7 or x = 0

_____

Many graphing programs will happily tell you the locations of x- and y-intercepts, so it is convenient to rewrite the equation so its value is zero at the solution points. We can do that by subtracting the right side constant to get ...

... 7|-7x -3| -21 = 0

7 0
3 years ago
What is the eighth term of the sequence below?
SpyIntel [72]

Answer:

A. 33

Step-by-step explanation:

Add 4 to each number

1. 5 is your first number

2. 5+4= 9 is your second number

3. 9+4= 13 is your third number

4. 13+4= 17 ...

5. 17+4= 21 ...

6. 21+4= 25 ...

7.25+4= 29 ...

8.29+ 4= 33 is your eight number

5 0
2 years ago
point q is located in ( -4 , 6) point r is located in ( 8,6) . what is the distance from pint q to point r
Hoochie [10]

Answer: 12

Step-by-step explanation: It’s on the same y axis and -4 to 8 is going to the right on a graph.

5 0
3 years ago
Someone help plz I need help
Firlakuza [10]

Answer:

-3 i think because it is low i am soooo sorry if its wrong i really wasnt trying to get points i wanted to help hope for the best

Step-by-step explanation:

4 0
2 years ago
The question is in the screenshot
Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

8 0
3 years ago
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