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2 years ago

If m∠10 = 70, then find the m∠14 and state the angle relationship.

Mathematics

1 answer:

Elenna [48]2 years ago

4 0

The measure of m∠14 is 110 degrees and the angle relationship is a supplementary angles

Let us assume that angle m∠10 and m∠14 are supplementary, this means that the sum of both angles will be 180 degrees.

Since the angles are supplementary, hence the required expression will be:

m∠10 + m∠14 = 180

Given that m∠10 = 70 degrees

70 + m∠14 = 180

m∠14 = 180 - 70

m∠14 = 110 degrees

Hence the measure of m∠14 is 110 degrees and the angle relationship is a supplementary angle.

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Use gcf distributive property to find the sum of 28 and 80.

Anna71 [15]

Step-by-step explanation:

The GCF of 28 and 80 is 4.

<u>Distribute 4 for 28 and 80, then solve:</u>

$4(7) + 4(20) = 28 + 80$

$4(7 + 20) = 28 + 80$

$4(27) = 28 + 80$

$108 = 80 + 28$

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2 years ago

PLEASE EXPLAIN!

stepladder [879]

Answer:

Step-by-step explanation:

5(2)(3)-2(2)+13+7(2)-6(2)(3)-4(2)+(2)(3)

30-4+13+14-36-8+6

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3 years ago

What’s the class width

aksik [14]

Answer:

Step-by-step explanation:

Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:

CW = UCL - LCL

Where,

CW= Class width

UCL= Upper class limit

LCL= Lower class limit

From the table above:

For class 1, CW = 64 - 60 = 4

For class 2, CW = 69 - 65 = 4

For class 3, CW = 74 - 70 = 4

For class 4, CW = 79 - 75 = 4

For class 5, CW = 84 - 80 = 4

Therefore, the class width of the grouped data = 4

6 0

3 years ago

Three ratios equivalent to 11/1

Damm [24]

Answer:

21 2

33 3

44 4

Step-by-step explanation:

think of them as equivalent fractions

8 0

3 years ago

Read 2 more answers

A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla

Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

$\frac{4}{12} * \frac{8}{11} = \frac{32}{132}$ or 0.2424 or 24.24%

8 0

3 years ago