Question

TWO SAMPLE PROPORTION z

Answer 1

A = he hits first free throw
B = he hits second free throw

P ( B|A')   = 48/53
P (B|A)    = 251/285 = 0.881

P(A) = 285/(53 + 285) = 285/338  = 0.843
P (B) = (251 + 48)/338  = 299/338 = 0.885

Hope this helps