Evaluate √x^2 + y^2 when x^2 =20 and y^2 =10
1 answer:
Answer:
5.477
Step-by-step explanation:
Here we have to get the value √ ( x²+y² ) in this question where the values of x² and y² are given to be 20 and 10 respectively.
Let A = √ ( x²+y² ) =√(20+10) {Since the value of x² =20 and that of y² =10}
⇒ A= √30 =5.477
Therefore, the value of √ ( x²+y² ) is 5.477. (Answer)
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