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3 years ago

"If a = − 9 and b = − 6, show that (a−b) ≠ (b−a)."

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

Step-by-step explanation:

LHS a - b = -9 - (-6) = -9 +6 = -3

RHS b-a = -6 - (- 9) = -6 +9 = 3

as LHS not equal to RHS

a-b not equal to b-a

Thus proven

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Step-by-step explanation:

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4 years ago

Please solve for y need ASAP

MrMuchimi

6(y+2) = 4(z+9)
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answer
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4 years ago

Find the value of x in the following quadrilateral

vlabodo [156]

Answer:

The answer is 63.31

Step-by-step explanation:

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6 0

3 years ago

Factor 4x^2 + 1x – 13

bulgar [2K]

Answer:

$(x - \frac{\sqrt{209} - 1}{8} )(x - \frac{-1 - \sqrt{209} }{8} )$

Step-by-step explanation:

FACTS TO KNOW BEFORE SOLVING :-

Quadratic Formula :-

Lets say , there's an equation ax² + bx + c.

$=> x = \frac{-b + \sqrt{b^2 - 4ac} }{2a} \: or \: \frac{-b - \sqrt{b^2 - 4ac} }{2a}$

SOLUTION :-

According to the question ,

a (Coefficient of x²) = 4

b (Coefficient of x) = 1

c (constant) = -13

By using quadratic formula ,

$x = \frac{-1 + \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4} \: or \: \frac{-1 - \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4}$

$=> x = \frac{-1 + \sqrt{209} }{8} \: or \: \frac{-1 - \sqrt{209} }{8}$

$=> (x - \frac{\sqrt{209} - 1}{8} ) \: and \: (x - \frac{-1 - \sqrt{209} }{8} )$ are the factors of 4x² + x - 13.

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3 years ago