Answer:
1.26 m^2 / s.
Step-by-step explanation:
The area A of the triangle = 1/2*7*12 sin x = 42 sin x where x is the angle between the lines.
Relation between the rates is
dA/dt + dA/dx * dx/dt
We are given that dx /dt = 0.06 rad/s.
A = 42 sin x
dA/dx = 42 cos x
So dA/dt = 42 cos x * 0.06
When x = π/3 ( I am assuming that π 3 means π divided by 3 ):
dA/dt = 42 cos π/3 * 0.06
= 1.26 m^2/s.
Answer:x=31
angle AOC = 124
angle BOC = 56
Step-by-step explanation:
We first need to solve for x to solve the rest. We would normally solve for x by setting 2 equations equal to each other, in this case however, we know that the two angles are adjacent and in total add up to 180. Therefore we combine like terms of both angles, and set them equal to 180.
So, we do
3x+31+2x-6=180 We will combine like terms
5x+25=180 Now we will do inverse operations
5x=155
x=31
We plug x into angle AOC to solve for it
3(31)+31= 124
180-124=56 or angle BOC because the whole angle is 180, and if we subtract 124 from 180 we get the remainder which is angle BOC
Or if you want,
2(31)-6=56
Answer:
18
Step-by-step explanation:
U=18
6times 3=18 and 18 divided by 3=6
Answer:
1 + 2 + 3 + 4 + 5 + 6 + 7 + ( 8 x 9 ) = 100
Step-by-step explanation:
<span>The equation of a circle with center C=(h,k) and radius r is:
(x-h)^2+(y-k)^2=r^2
In this case the center is the point C=(a,b)=(h,k)→h=a, k=b, then:
(x-a)^2+(y-b)^2=r^2
We can apply the Pythagorean Theorem to find the distance between any point of the circle P=(x,y) and the Center C=(a,b). This distance must be equal to the radius of the circle:
A^2+B^2=C^2, where A and B are the legs of the triangle and C is the hypothenuse.
In this case, according with the figure: The legs of the triangle are:
A=x-a
B=y-b
And the hypothnuse C=r
Then replacing in the Pythagorean Theorem:
(x-a)^2+(y-b)^2=r^2
Equal to the equation of the circle </span>(x-a)^2+(y-b)^2=r^2
