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jeyben [28]
3 years ago
15

"If a = − 9 and b = − 6, show that (a−b) ≠ (b−a)."

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

Step-by-step explanation:

LHS  a - b = -9 - (-6) = -9 +6 = -3

RHS  b-a = -6 - (- 9) =  -6 +9 = 3

as LHS not equal to RHS

a-b not equal to b-a

Thus proven

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Please solve for y need ASAP
MrMuchimi
6(y+2) = 4(z+9)
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4 years ago
Find the value of x in the following quadrilateral
vlabodo [156]

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Step-by-step explanation:

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6 0
3 years ago
Factor 4x^2 + 1x – 13
bulgar [2K]

Answer:

(x - \frac{\sqrt{209} - 1}{8} )(x - \frac{-1 - \sqrt{209} }{8} )

Step-by-step explanation:

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

<em>Quadratic Formula :-</em>

Lets say , there's an equation ax² + bx + c.

=> x = \frac{-b + \sqrt{b^2 - 4ac} }{2a} \: or \: \frac{-b - \sqrt{b^2 - 4ac} }{2a}

<u>SOLUTION :-</u>

According to the question ,

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  • b (Coefficient of x) = 1
  • c (constant) = -13

By using quadratic formula ,

x = \frac{-1 + \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4} \: or \: \frac{-1 - \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4}

=> x = \frac{-1 + \sqrt{209} }{8} \: or \: \frac{-1 - \sqrt{209} }{8}

=> (x - \frac{\sqrt{209} - 1}{8} ) \: and \: (x - \frac{-1 - \sqrt{209} }{8} ) are the factors of 4x² + x - 13.

6 0
3 years ago
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