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motikmotik
3 years ago
11

Anybody can help me out?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

answer D

Step-by-step explanation:

Hello

(fog)(x)=f(g(x))=|4x+9|

so g(x)=4x+9

and f(x)=|x|

hope this helps

You might be interested in
the sum of two numbers is 49.Twice the smaller number is 97 less than 3 times the larger number.What are the numbers. help mee I
kondaur [170]

Answer:

smaller number is 10

larger number is 39

Step-by-step explanation:

a = small number

b = larger number

a + b = 49

2a = 3b - 97

substitute 49-a into second equation for b

2a = 3(49-a) - 97

2a = 147 - 3a - 97

5a = 50

a = 10

b = 39

7 0
3 years ago
What is two solutions for x>6
Daniel [21]

7>6

8>6

9>6

etc.

Possible values for x:

x=7

x=8

x=9

etc.

4 0
3 years ago
Select each equation which is equivalent to 60% of 25.
loris [4]

Answer:

0.6 x 25 = x

Step-by-step explanation:

60% of 25

= 60/100 x 25

= 0.6 x 25

= 15

Though the question states as in a "select-all question," Only answer 0.6 x 25 = x will be correct.

8 0
3 years ago
Read 2 more answers
The nth term of a sequence is 2n-1.
Zinaida [17]

Answer:

25,31,37

Step-by-step explanation:

n should be positive integer number. The three numbers in both sequences have different term number n but same value. We can equalize each nth term in the question to "a" which represents one of the three numbers.

a=2n-1, then n=(a+1)/2

a=3n+1, then n=(a-1)/3

remember the two n above are different but both should be positive integer. That means, we have to find the "a" number that gives me an integer n for the first equation. The possible numbers between 20 to 40 are 22,25,28,31,34,37,40.

The possible numbers for the second equation are 21,23,25,27,29,31,33,35,37,39.

Now find the common numbers between the two sets above. They are 25,31,37

6 0
3 years ago
(1+(0.065÷365))^365t=4
marta [7]
This is the future value quadrupled in t years at an annual interest rate of 6.5% compounded daily.  We need to find t.

1*(1+0.065/365)^(365t)t=4
take log on both sides,
365t(log(1+0.065/365)=log(4)
=>
365t=log(4)/log(1+0.065/365)
t=(log(4)/log(1+0.065/365))/365
=(1.38629/.000178066)/365
=21.33 years

Check with the rule of 69, applicable to continuous compounding (an approximation to current problem) to double money, it take 69/interest rate in % years.
=69/6.5
=10.62 years
To double twice (quadruple), it takes twice 10.62
=21.24 years, not that far from 21.33 that we got earlier.
7 0
3 years ago
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