Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
1 is thousands
6 is tens
2 is tenths
5 is hundreds
All real numbers for the domain
Answer:
25
Step-by-step explanation:
If (1/5)^2 equals 1/25, then (1/5)^-2 should be the opposite.
(1/5)^-2 equals 25
Answer:
The probability that they will both be on time is 12/25.
Step-by-step explanation:
John is late 20% of the time.
So, he is prompt 80% of the time.
Ted is late 40% of the time.
So, he is prompt 60% of the time.
Since, both the events are independent,
p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)
× 
= 0.80 × 0.60
= 0.48 or 48%
Hence, the probability that they will both be on time is 12/25.
