As an estimation we are told £3 is €4. Convert €96 to pounds
2 answers:
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Answer:
The correct option is (B) 0.173.
Step-by-step explanation:
The law of total probability states that:
The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:
Then the probability of intersection of A and B is:
Denote the events as follows:
<em>H</em> = a man died from causes related to heart disease.
<em>X</em> = a man had at least one parent who suffered from heart disease
The information provided is:
The probability that a man randomly selected from this group died of causes related to heart disease, given that neither of his parents suffered from heart disease is, .
Compute the value of as follows:
Thus, the probability that a man randomly selected from this group died of causes related to heart disease, given that neither of his parents suffered from heart disease is 0.173.
The correct option is (B).
Answer:
1) There are 100 carbon-14 atoms in the wood when it died
2) A function that models the number 'N' of carbon-14 atoms present in the wood (t) years after it died is presented as follows;
Step-by-step explanation:
The given parameters are;
The number of carbon-12 for each carbon-14 atom ≈ 10¹² carbon-12 atoms
The number of carbon-12 in the piece of wood = 10¹⁴ carbon-12 atoms
The number of carbon-14 in the piece of wood = 40 carbon-14 atoms
The number of carbon-12 in an organism = Constant
The number of carbon-14 in an organism = Decays
1) Given that the number of carbon-12 in an organism is constant, and there are 10¹² carbon-12 atoms per each carbon-14 atom, therefore, we have;
The number of carbon-12 atoms in the wood when it died = 10¹⁴ carbon-12 atoms
The number of carbon-14 atoms in the wood when it died = (10¹⁴ carbon-12 atoms)/(10¹² carbon-12 atoms/(carbon-14 atom)) = 100 carbon-14 atoms
The number of carbon-14 atoms in the wood when it died = 100 carbon-14 atoms
2) The half life of a radioactive isotope is given by the following formula;
The half life of carbon-14 atoms, ≈ 5,730 years
N₀ = The amount of carbon-14 present in the wood when it died = 100 carbon-14 atoms
Therefore, we have;
The number, N, of carbon-14 atoms present in the wood (t) years after it died is given as follows;