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Sauron [17]
3 years ago
13

The total cost (in dollars) for a company to manufacture and sell x items per week is C=40x+180, whereas the revenue brought in

by selling all x items is R=68x−0.4x2. How many items must be sold to obtain a weekly profit of $300?
Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

The company needs to sell either 30 or 40 items.

Step-by-step explanation:

We are given that the cost for selling <em>x</em> items given by the function:

C(x)=40x+180

And the revenue for selling <em>x</em> items is given by:

R(x)=68x-0.4x^2

The profit function is the cost function subtracted from the revenue function:

P(x)=R(x)-C(x)

Substitute and simplify:

\displaystyle \begin{aligned} P(x)&=(68x-0.4x^2)-(40x+180)\\&=68x-0.4x^2-40x-180\\&=-0.4x^2+28x-180\end{aligned}

To find how many items must be sold in order to obtain a weekly profit of $300, we can let <em>P</em> equal 300 and solve for <em>x</em>. So:

300=-0.4x^2+28x-180

Solve for <em>x</em>. Subtract 300 from both sides:

-0.4x^2+28x-480=0

We can divide both sides by -0.4:

x^2-70x+1200=0

Factor:

(x-40)(x-30)=0

Zero Product Property:

x-40=0\text{ or } x-30=0

Solve for each case:

x=40\text{ or } x=30

So, in order to obtain a weekly profit of $300, the company need to sell either 30 <em>or</em> 40 items.

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