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AleksandrR [38]
3 years ago
5

María compró 25.665 lapiceros de color azul para repartirlos entre sus 124 amigos y ella ¿Cuántos tapicero le tocó a cada uno?¿

Cuántos sobraron?​
Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

maria compro 25665 lapiceros de color azul para repartirlos ...brainly.lat › Matemáticas › Secundaria

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Aug 16, 2016 — maria compro 25665 lapiceros de color azul para repartirlos entre sus 124 amigos y ella ¿cuantos lapiceros le toco a cada uno? 1.

1 answer

Si María compró 25665 lapiceros de color azul para ... - Brainlybrainly.lat › Matemáticas › Secundaria

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Nov 29, 2018 — Si María compró 25665 lapiceros de color azul para repartirlos entre sus 124 amigos y ella ¿Cuántos lapiceros le tocó a cada uno?¿Cuántos lapiceros sobraron? 2. Ver respuestas. Inicia sesión para comentar ...

2 answers

maría compro 25,665 lapiceros de color azul para repartirlos ...brainly.lat › ... › Universidad

Translate this page

May 29, 2020 — maría compro 25,665 lapiceros de color azul para repartirlos entre sus 124 amigos y ella ¿cuántos lapiceros le tocó a cada uno?¿cuántos lapiceros sobraron? 2. Ver respuestas. Inicia sesión para comentar ...

Step-by-step explanation:

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Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

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The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

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3 years ago
Zeno jumped 8 meters. Then he jumped half as far again (4 meters). Then he jumped half as far again (2 meters). So after 3 jumps
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Find the tangent of ∠I.
Nady [450]

Answer:

tanI = \frac{\sqrt{70} }{5}

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = (\sqrt{95} )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = \sqrt{70}

Then

tanI = \frac{opposite}{adjacent} = \frac{GH}{GI} = \frac{\sqrt{70} }{5}

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Step-by-step explanation:

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Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
arsen [322]

we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

x'=-8sin(8t),y=8cos(8t),z=-8tan(t)

now, we can plug these values

L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt

now, we can simplify it

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L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt

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now, we can solve integral

\int \:8\sec \left(t\right)dt

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now, we can plug bounds

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=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

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3 years ago
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