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saul85 [17]
3 years ago
7

B is the midpoint of AC. A has coordinates (- 8, 11) , and B has coordinates (11, 10) . Find the coordinates of C

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer: NOPE

Step-by-step explanation:

SOrry bro its -24

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PLS HELP !!! U WILL GET 13 POINTS AND BRAINLIEST !!THIS IS A TEST AND I NEED TO SHOW WORK PLS PLS HELP AND ONLY ANSWER IF U KNOW
erastova [34]

Answer:

This should be parallel.

Step-by-step explanation:

Two lines are said to be parallel only if their slope matches. They are said to be perpendicular only if the slopes are negative reciprocals.

Here, you should put both equations in slope intercept form which is y=mx+b. The letter "M" represents the slope of both equations.

2y-6=3x+4 turns into 2y=3x+10 after adding 6 and into y=3/2x+5 after dividing the equation by 2. The slope for this equation is 3/2.

8y=12x+8 must be divided by 8 to be in slope intercept form. This equation becomes y=3/2x+1. Here the slope is also 3/2.

The slopes for each equation match making these lines parallel.

4 0
2 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

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Step-by-step explanation:

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proved##

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