$9.50 I believe, I hope this helps !
No, in order for this to be correct, you'd have to move BOTH decimals in the same direction the same amount of places.<span />
Answer:
It's A.
Step-by-step explanation:
Let's look at option A:
From the second equation y = -10 - x. Substituting in the first equation:
-10 - x = x^2 + 3x - 5
x^2 + 4x + 5 = 0
Checking the discriminant b^2 - 4ac we get 16 - 4*1*5 = -4 so there are no real roots. (A negative discriminant means no real roots).
So A has no real solution.
B.
x^2 + 3x - 5 = (20 - 4x)/5 = 4 - 0.8x
x^2 +3.8x - 9 = 0
b^2 - 4ac = (3.8)^2 - 4*1*-9 = 50.44 (positive) so there are real roots.
C.
x^2 + 3x - 5 = -9 - x
x^2 + 4x + 4 = 0
b^2 - 4ac = 4^2 - 4*1*4 = 0 so there are real roots.
First, what we should do is simplify both expressions.
We have then:
Expression 1:
(3x2) 3x ^ 2
(9x ^ (2 + 2))
9x ^ 4
Expression 2:
(3x ^ 3) ^ 2 (x ^ 2)
(9x ^ 6) (x ^ 2)
(9x ^ (6 + 2))
9x ^ 8
Answer:
The exponents on Expression # 2 are greater than the exponents of Expression # 1.
(8> 4)
