Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (
y + 2)(y + 2) = 0 y = –2 Which is the true solution to the radical equation y + 1 = ? y = –2 y = 1 y = 2 There are no true solutions to the equation.
1 answer:
Answer:
There are no true solutions to the equation.
Step-by-step explanation:
<u><em>The correct equation is</em></u>

Solve for y
squared both sides






<em>Verify</em>
substitute the value of y in the original expression

----> is not true
therefore
There are no true solutions to the equation.
You might be interested in
Answer:
5
Step-by-step explanation:
xy-5
plug in 5 for x and 2 for y
5*2-5
multiply
10-5
subtract
5
6(7n – 5m) + 8m
42n - 30m + 8m
42n -22m
Answer: 42n-22m
Answer:
6
Step-by-step explanation:
All sides of triangle EFD have x6 of BAC.
E.g.: BA = 2. ED = 2 x 6 = 12
Answer:
-3
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept.
Answer: $6
Step-by-step explanation: