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Maslowich
3 years ago
10

HELP PLEASE !! IS IT A, B OR C

Mathematics
1 answer:
Schach [20]3 years ago
8 0
C is the answer yeah yeah
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Answer this please !
SpyIntel [72]

Answer:

6

Step-by-step explanation:

\frac{y}{2} =x^{2} -7

\frac{a}{2} =2^{2} -7

\frac{a}{2} =-3

a=-6

\frac{b}{2} =1^{2} -7

\frac{b}{2} =-6

b=-12

From the calculations above, we learn that line l and the curve intersect at (2, -6) and (1, -12). Next, we will set up a system of linear equations to solve for the slope and the y-intercept of line l.

-6=2m+b        

-12=m+b

-24=2m+2b

18=-b

b=-18

-12=m-18

m=6

Therefore, the slope of line l is 6.

3 0
2 years ago
Read 2 more answers
Help me on this please!
sertanlavr [38]

Answer:

B-a population growth of 3% each year

Step-by-step explanation:

The 1.03 would mean that the exponential function is increasing by 3% every year because it is 0.03 units above 1.

6 0
2 years ago
Bella works at the grocery store and has 453 oranges to fit into 17 boxes. She fills all of the boxes with exactly the same numb
LUCKY_DIMON [66]

Answer:

It would be 7701

Step-by-step explanation: hope this helps!

6 0
3 years ago
Read 2 more answers
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
HELP ME PLS IM DESPO
gogolik [260]
There is a 1/3 chance. Add up the shaded parts for a total of 120 degrees. 120/360 is 1/3
7 0
3 years ago
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