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makvit [3.9K]
2 years ago
12

the length of a rectangular sign is 5 times its width. If the sign's perimeter is 24inches, what is the signs area

Mathematics
1 answer:
anastassius [24]2 years ago
6 0

Answer:

20 square inches

Step-by-step explanation:

Set width of sign to x.

Set length of sign to y.

5x=y

2(x+y)=24 inches

2(x+5x)=24 inches

12x=24 inches

width = 2 inches

length = 10 inches

Area = 20 square inches

PLEASE GIVE BRAINLIEST

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I'd suggest rewriting both mixed numbers as improper fractions.  Then we'd have:

14/3 and 5/3

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Analyze the scatterplot below, what prediction can you make about the group of students used in the study from the graph below?
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2 years ago
An insured has $5,000 of medical coverage on a personal auto policy at the time of a covered accident. The insured and two passe
Vlad1618 [11]

Answer: 14,000 $ Max will be paid and 5000$ per person.

Step-by-step explanation:

In this case, we can assume the following:

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3 years ago
Hi . I'm kinda stuck on this question . <br>Help please. <br>Workings please​
Gre4nikov [31]

Answer:

\large \boxed{\text{Q31, D. 6.00 F; 32. C. N21.75; Q33. A. 168.00 F}}

Step-by-step explanation:

Your graph is hard to read, so I re-drew it as best I could.

You must first develop an equation relating francs and naira.

The line goes through the origin, so the general equation is

y = kx

One of the points is (40,240).

\begin{array}{rcl}F & = &k \times N\\240 & = &k \times 40\\k & = & \dfrac{240}{40}\\\\k&=&\textbf{6 F/N}\\\end{array}\\\text{The equation is $\large \boxed{\mathtbf{F = 6 N}}$}

Q 31.

\begin{array}{rcl}F & = &6N\\& = & 6 \times 1.00\\& = & \mathbf{6.00}\end{array}\\\text{The equivalent value of N1.00 is $\large \boxed{\textbf{6.00 F}}$}

Q 32.

\begin{array}{rcl}F & = &6N\\130.5& = & 6 N\\N&=& \dfrac{130.5}{6}\\\\& = & \mathbf{21.75}\\\end{array}\\\text{The equivalent value of 130.5 F is $\large \boxed{\textbf{N21.75}}$}

Q 33.

\begin{array}{rcl}F & = &6N\\& = & 6 \times 28.00\\& = & \mathbf{168.00}\end{array}\\\text{An amount of N28.00 is $\large \boxed{\textbf{168.00 F}}$}

6 0
2 years ago
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