Question

MULTIPLYING POLYNOMIALS

Answer 1

$(n-4)(n-6) = n^2-10n+24\\\\(a+5)(a-6) = a^2 -a-30\\\\(4b + 6)(b-4) = 4b^2 -10b-24$

Solution:

Multiplying polynomials:

Multiplying polynomials is same like multiplying numbers

First, multiply the first term in the first parentheses by all the terms in the second parentheses

Now we multiply the second term in the first parentheses by all terms in the second parentheses and add them to the previous terms

$1)\ (n-4)(n-6)$

$(n-4) \times (n-6) = n^2 -6n -4n +24\\\\Simplify\\\\(n-4) \times (n-6) = n^2 -10n + 24$

Now let us multiply the second given option

$2)\ (a+5)(a-6)$

Multiply them together

$(a+5)(a-6) = a^2 -6a + 5a - 30\\\\Simplify\ by\ combining\ the\ like\ terms\\\\(a+5)(a-6) = a^2 -a -30$

Now let us multiply the third given polynomial

$3)\ (4b+6)(b-4)$

Multiply them together

$(4b+6)(b-4) = 4b^2 -16b + 6b - 24\\\\Simplify\ by\ combining\ the\ like\ terms\\\\(4b+6)(b-4) = 4b^2 -10b -24$

Thus the given polynomials are multiplied