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Sidana [21]
3 years ago
9

Whats the sum of 2x and 3

Mathematics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

5x maybe dont take my word

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The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
12 - 16 ÷(-4)<br><br> A. -1<br> B. 1<br> C. 8<br> D. 16
Naya [18.7K]

Answer:

D. 16

Step-by-step explanation:

Do the division first

-16 ÷ (-4) = 4 then do the sum

12 + 4 = 16

7 0
3 years ago
A basin has the shape of a prism. What is the capacity of this basin? *
dolphi86 [110]
I think it’s c.....
3 0
3 years ago
Which equation can be used to find the solution of (1/3)^d−5=81 ?
horsena [70]

Let's solve your equation step-by-step.

Step 1: Add 5 to both sides.

\frac{1}{3}^{2} -5+5=81+5

\frac{1}{3}^d =86

Step 2: Solve Exponent to get.

d = −4.054522   or -4.05  hope this helps


4 0
3 years ago
How do you use the order of operations to evaluate expressions with exponents?
IgorLugansk [536]
Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations
5 0
3 years ago
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