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HACTEHA [7]
3 years ago
8

Help pleaseeee

Mathematics
1 answer:
laiz [17]3 years ago
6 0

Answer:

x=15

Step-by-step explanation:

so we are given one angle 90, although x is used in both so you can add them. We know that the sum of angle measures in a triangle is 180 so the equation is: 90+6x=180

subtract 90 from both sides: 6x=90

divide by 6: x=90/6

simplify: x=15

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stellarik [79]

Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

\frac{36*24}{100*10}

=\frac{864}{1000}

Now we can convert this back to decimal

864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.

Answer=0.864

7 0
3 years ago
I need help im not understanding how to do this
galina1969 [7]

Answer:

(c, b)

Step-by-step explanation:

Add the coordinates together and divide by 2

x coordinates: 2c + 0 = 2c, divided by 2 = c

y coordinates: 0 + 2b = 2b, divided by 2 = b

3 0
2 years ago
Read 2 more answers
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
4 years ago
Help help help pls help
Brilliant_brown [7]

AB = 6.1

\sin(c)  =  \frac{ab}{x}  \\  \\ ab = 7.7 \sin(52)  \\ ab = 6.06

6 0
3 years ago
Read 2 more answers
I’m not really sure how to do this but if someone could please help with explanation on how to do it thank you
masya89 [10]

Answer: a because it’s using the commutative property of addition meaning it’s the same mathematical statement, it’s just moved around

Step-by-step explanation:

3 0
3 years ago
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