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geniusboy [140]
2 years ago
9

Find the slope of the line.

Mathematics
2 answers:
elena55 [62]2 years ago
4 0

Answer:

The slope is 0.

Step-by-step explanation:

The slope of any horizontal line is zero.

almond37 [142]2 years ago
4 0

Answer:

0

Step-by-step explanation:

Since the line is horizontal(left-right), the slope is zero.

If the line had been vertical(top-bottom), the slope would have been zero.

If there was an applicable rise over run, the slope would have been a(the difference between points along the <em>y-axis</em>) over b(the difference between points along the <em>x-axis</em>).

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What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64
marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are 2x+y\geq 8 -------(1)

x+y \geq 6   ------------- (2)

x \geq 0, y \geq 0  -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, 2\times 0+0\geq 8⇒0\geq 8 ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, 0+0\geq 6⇒0\geq 6 ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4),  C= 46

At B≡(6,0),  C= 42

Thus at B, C is minimum, And its minimum value = 42


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4 pi cm

Step-by-step explanation:

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Solve for m. -19m − 19 = 4m − 4m + 19
dangina [55]
-19m-19 = 4m-4m+19
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If log a = x and log b = y, then log (ab2) equals
mylen [45]

Answer:

The answer for log(ab²) is x + 2y.

Step-by-step explanation:

You have to apply Logarithm Law,

log(a)  +   log(b) \:  ⇒ \:  log(a \times b)

log( {a}^{n} )  \: ⇒ \: n log(a)

In this question, you have to seperate it out :

log(a {b}^{2} )  =  log(a)  +  log( {b}^{2} )

log( {b}^{2} )  = 2 log(b)

let \:  log(a)  = x

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log(a {b}^{2} )  =  log(a)  + 2 log(b)

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