A) The possible three-course selections are as shown below.
B) The likelihood of selecting the combinations is 0.1 since there are 10 combinations in total.
<h3>How to solve probability combinations?</h3>
A combination operator can be used when we need to find the number of ways to select "k" items from a set of "n" items. It is also called a 'choose' operator where it is read as 'n choose k' and is represented and calculated as given below
From the choices given, there are 5 courses which are given below:
EPR 605
EPR 643
EPR 648
EPR 674
EPR 681
We need to find the combinations of 3 of these given 5 courses, which are given below (omitting the course code, EPR):
605-643-648
605-643-674
605-643-681
605-648-674
605-648-681
605-674-681
643-648-674
643-648-681
643-674-681
648-674-681
10 of the given choices of combinations are possible since they do not include a repeated course number.
The likelihood of selecting the combination of EPR 681, EPR 648, and EPR 605 is 0.1 since there are 10 combinations in total.
Complete question is;
A student entering a doctoral program in educational psychology is required to select three courses from the list of courses provided as part of his or her program. List all possible three-course selections. Comment on the likelihood that EPR 681, EPR 648, and EPR 605 will be selected. Select all the possible three-course selections below.
A. 648, 674, 605
B. 681, 648, 605
C. 681, 674, 605
D. 681, 681, 648
E. 674, 643, 674
F. 674, 605, 643
G. 681, 648, 674
H. 681, 681
I. 681, 648, 643
J. 648, 605, 643
K. 648, 674, 643
L. 681, 605, 643
M. 643, 694, 643
N. 681, 674, 643
Read more about Probability Combinations at; brainly.com/question/3901018
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Answer:
No.
Step-by-step explanation:
Let's start by simplifying the first expression:
Remove the parentheses:
Combine like terms:
(Assuming that none of the variables are equivalent to 0)
126 times 10 and whatever that answer is is the volume
<span>(x + 3,y - 2)
</span>
=B'(-1, 1)
x = -4, y = 3
(x,y)
Answer:
No of white balls = 5
Step-by-step explanation:
Given that,
Total no of red balls = 4
Total no of green balls = 6
The probability of not drawing a white ball in one draw be, 
We need to find the number of white balls. Let there are x balls.
The probability of drawing a white ball = 1 - the probability of not drawing a white ball
= 1 -2/3
= 1/3
Using the formula for solving probability of having a white ball.
Hence, there are 5 white balls.
