Answer:
208 divided by 2
100+2
402-300
Step-by-step explanation:
Answer:
53.13
Step-by-step explanation:
Simplify both sides of the equation.
<span><span><span><span>3/5</span>n </span>+ 15 </span>= <span><span><span>2/5</span>n </span>+ 10
</span></span>Subtract 2/5n from both sides.
<span><span><span><span><span>3/5</span>n </span>+ 15 - </span><span><span>2/5</span>n </span></span>= <span><span><span><span>2/5</span>n </span>+ 10 - </span><span><span>2/5</span>n</span></span></span><span><span><span><span>15</span>n </span>+ 15 </span>= 10
</span>Subtract 15 from both sides.
<span><span><span><span><span>1/5</span>n </span>+ 15 - </span>15 </span>= <span>10 - 15</span></span><span><span><span>1/5</span>n </span>= -<span>5
</span></span>Multiply both sides by 5.
<span><span>5 </span></span>× (1/5n) = (5) × (−5)<span>n = -<span><span>25
Answer: n is -25.</span></span></span>
The outlier would be shown as a dot so the answer is B. 45
The interquartile range is 28 - 18 = 10
A simple rule is that points more than 1.5xIRQ above or below the medians is an outlier and is shown as a point.
28 + 1.5x10 = 43. 45 is above this value.
We use algebraic equations in our daily lives without knowing it. For example, when we go shopping, calculate grocery expenses, or even fill our gas tanks, we are using equations. Let's say we needed to fill our gas tank, but we only had $15.00 to do so. If the price of gas is $3.00 per gallon, how many gallons could we buy? We use the simply algebraic equation of
to calculate the total gallons that can be bought. x = the money we have. y = price per gallon of gas.
= 5. So with $15.00, we can buy 5 gallons of gas; and that is just one example of using an algebraic equation in everyday life!
