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trasher [3.6K]
3 years ago
13

A class of 20 boys and 15 girls is divided into n groups so that each group has x boys and y girls. Find x, y and n. what values

are referred in this class
Mathematics
1 answer:
melamori03 [73]3 years ago
4 0
20 = 2 x 2 x 5
15 = 3 x 5

common divisor (CD) of 20 and 15 is 5 so n should be 5 and each group has 4 boys and 3 girls.

If there are more than one CD, then there are more than one answer.

If they ask for the largest number of groups, greatest common divisor (GCD) will be the answer.
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Creating a function machine can be time consuming and awkward. The
IrinaK [193]

The ordered pairs for :

(a) Y = 9-4x are (-2,17), (5,-11) ,(2/3,19/3) and (0.75,6).

(b) Y = 1/x are (-2.-1/2), (5,1/5), (2/3,3/2) and (0.75,1.33)

We are given two functions for which corresponding y-values need to be found for the given x-values so that ordered pairs of the form (x, y) can be formed.

Consider the function Y = 9-4x.

When x = -2, y = 9-(4 x -2) = 17

When x = 5, y = 9-(4 x 5) = -11

When x = 2/3, y = 9-(4 x 2/3) = 9-(8/3) = 19/3

When x = 0.75, y = 9-(4 x 0.75) = 6

So the ordered pairs are: (-2,17), (5,-11) ,(2/3,19/3) and (0.75,6).

Consider the function Y = 1/x

When x = -2, y = 1/-2 = -1/2

When x = 5, y = 1/5

When x = 2/3, y = 1/(2/3) = 3/2

When x = 0.75, y = 1/0.75 = 1.33

So the ordered pairs are: (-2.-1/2), (5,1/5), (2/3,3/2) and (0.75,1.33)

Learn more about ordered pairs at brainly.com/question/20348140

#SPJ9

6 0
1 year ago
Find the area of this figure
tankabanditka [31]

Answer:

it should be 2,744. i believe

Step-by-step explanation:


4 0
3 years ago
The graph shows the depth, y, in meters, of a shark from the surface of an ocean for a certain amount of time, x, in minutes:
Tcecarenko [31]

The answers are:

  • Part A: The slope of AB and BC are the same.
  • Part B :The initial value is 60 m and the slope is 40 m/min.

<h3>What is the triangles about?</h3>

Note that the graph depict the depth, y, in meters, of a shark that moves from the surface of an ocean for a given amount of time, x, in minutes.

So:

Part A :

We  look at the two right triangles:  Δ ABD and Δ BCE, and where D(2,100) and E(1,60) points.

Since the  triangle are the same and thus, the slope of line segment AB: tan θ = AD/BD

= 140 - 100 / 2 - 1

= 40

Since the the slopes of line segment BC will be:

tan a = BE/CE

= 100 - 6 / 1 - 0

= 40

So, θ = α and the slope of AB and BC are similar.

Part B :

Using the graph, one can see that  the initial value of the graph is 60 m and it stands for the initial position of the shark

e.g.  at point t = 0 min, the shark was seen at a depth of 60 m from the water surface.

So therefore, since the slope of the graph is 40 it implies that the rate of change of distance from the Ocean surface of the shark in regards to the  time in minutes have to be 40 m per min.

Therefore, The answers are:

Part A: The slope of AB and BC are the same.

Part B :The initial value is 60 m and the slope is 40 m/min.

Learn more about triangles from

brainly.com/question/20983131

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3 0
1 year ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
2 years ago
How can you the unit rate on a graph that goes through the origin ?
Nonamiya [84]
It must be about the origin in order to do that
5 0
3 years ago
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