Answer:
3g^2 - 2g + 12
Step-by-step explanation:
3g^2 - 7g + 5g + 12
-7g + 5g = -2g
There were an on-time departure for all 3 flights in 5 of the simulations.
Hello Bubbleshi !
The first step you need to do is get everything in like terms.
- 1/6 and - 7 /4
Look at the denominator (number on the bottom)
6 and 4 go into 12, so lets check that out.
-1/6 , how can we get 12 from the denominator? Multiply it by 2.
So you multiply both the numerator (number on the top) and the denominator.
-1/6 becomes -2/12.
With -7/4, you want to get the 4 as a 12 (like terms!) so once again you multiply it by 3, and multiply the numerator as well.
-7/4 becomes -21/12.
-2/12 + (-21/12) is your final form of the problem.
You add -2 and -21 in the numerator, which is -23.
So its -23/12 which is your final answer.
Let me know if you need any more help!
The Solution is in the above attachment...Please refer it...
<u>ANSWER</u>
a=<em>7</em><em> </em><em>,</em><em> </em>b= <em>7</em><em>-</em><em>4</em><em>i</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Regards</em><em>,</em>
<em>Leukonov</em><em>/</em><em>Olegion</em><em>.</em>
Answer:
r=-2/3 or r= 6
Step-by-step explanation:
To solve this equation to find r, first subtract 5 from both sides.
3r² - 16r -7 -5= 5 -5
3r² - 16r -12= 0 (simplify)
(3r + 2)(r - 6)= 0 (factorise the equation)
3r+2=0 or r-6=0
3r= -2 or r= 6
r= -2/3