Answer:
angel BAC=CBD
BAC=43°because CBD also 43°
The value of p and q is 2 , -8 , The nth term of the series is given by 3 * n² + n-2 , the 40th term is 4838 .
<h3>What is a quadratic Sequence ?</h3>
A sequence which has n term in its sequence , The difference of the consecutive number is not same , its second difference is same.
The sequence is given as 7; p; -3;q;...
for a linear pattern
7-p = p- (-3) = -3-q
2p = 4
p = 2
and
2+3 = -3 -q
5 +3 = -q
q = -8
The value of p and q is 2 , -8
A quadratic sequence is defined as 2; 12; 28; 50
The next two terms are 77 and 112.
3. The T40 of the sequence is
The nth term of the series is given by
3 * n² + n-2
therefore 40th term is
3 *40² + 40-2
3 *1600 +38
4838
Therefore the 40th term is 4838 .
To know more about Quadratic Sequence
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The answer would be 39/250000
Answer:
Use the Pythagorean Theorem to calculate the length of the sides of a right triangle. A TV cut in half on the diagonal is a right triangle.
a^2 + b^2 = c^2
a is the width of the TV
b is the height of the TV
c is the diagonal size of the TV
a is equal to the length of b plus 15, and c is equal to 75. If we out those values into the formula, we get this:
(b+15)^2 + (b)^2 = (75)^2
Factoring that out, we get:
(b)^2 + 225 + (b)^2 = 5625
Then..
2b^2 = 5625 - 225
2b^2 = 5400
b^2 = 5400/2
b^2 = 2700
b = ✓2700
b = 51.9615242271 (round it to an even 52)
Next, we know that a = b + 15, so a = 67.
Therefore, the width of the TV is 67 inches, the height is 52 inches, the diagonal is 75 inches, and you have a very strangely shaped television with a 1.288 (approximately 5:4) aspect ratio. Older “square” TVs mostly had a 1.33 (4:3) ratio, and new TVs are usually either 16:9 (1.77) or 21:9 (2.33). While it's not impossible that you have an old square TV with a 75 inch diagonal, it's pretty unlikely…
Step-by-step explanation:
Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).
Center of center of dilation is (2,-2).
Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.
Now, we need to apply rule for dilation with the scale factor 5/3.
Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.
We will extend RS to 5 units and TS also 5 units.
The new resulting image would be dilated triangle by a scale factor 5/3.
New coordinates would be
<h3>R'(2,3), S'(2,-2) and T'(-3,-2)</h3>