Answer:
8/3
Step-by-step explanation:
Because all 4 angles are congruent, the sides are proportional.
the scale factor is 5/30 = 1/6.
meaning x = 16(1/6)=8/3.
A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat?
Answer:
the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat is 0.1
Step-by-step explanation:
We know that probability= number of required outcomes /number of all possible outcome.
From the given information;
the number of required outcome is guessing a 9-digit = 1 outcome
the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.
Since there are only 9-digit that opens the lock;
the probability of a person correctly guessing a 9-digit entry code is
P = 0.1
Answer:
16 square inches.
Step-by-step explanation:
Split the shape into a rectangle and square. To solve for square, just mulitple the 2 sides (2 x 2) and you get an area of 4. To solve for the rectangle, you can multiple the 6 and 2 to get the area of 12. Add the 4 and 12 together and you get 16 square inches. Hope this helps!
Answer:
5 ounces
Step-by-step explanation:
Let the capacity of jug be j, bottle be b
Okay
we have the rate of change of AC = d(AC)/dt = -2
the rate of change od BC = d(BC)/dt
area = (1/2) *AC) (BC)
taking differential on both sides we ge
d(A)/dt = 1/2){ (BC) d(AC)/dt + (AC) d(BC)/dt)}....(1)
again
when AC= 3
applying pythagorous thm
we get
(5)^2 =(3)^2 +(BC)^2
hence we get BC = 4
now we need to find d(BC)/dt
we have
(5)^2 = (AC)^2 +(BC)^2
taking differenial
0=2(AC) d(AC/dt) +2BC d(BC)/dt
that is
d(BC)/dt = -(3) *(-2)/4 ..(at AC =3)
hence
d(BC)/dt = 3/2
substituting these values in equation (1)
d(A)/dt = (1/2) {4 * -2 + 3 *3/2}
which gives
<span>d(A)/dt = -7/4
</span>The rate, in square feet per second, at which <span>the area is changing when AC = 3 is -7/4 ft/sec.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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