9/6 = 1 3/6
⇒ which equal 1 1/2
Hello there!
amd 
Let me start with 8^-2
8^-2 = 1/8 * 8
8^-2 = 1/64
which equals to 0.015625 in decimal
8^ 0 = 1
Yep, that's the answer! Easy, isn't? Well you may have been wondering why 8^0 is equal to 1.
I quoted an explanation online that says: Think of "multiplication" as always including an extra "1" as a multiplier.
So it'd be like
8^ 0
8/8 = 1
Remember: Whenever a number has an exponent 0, the answer MUST be 1.
Thus,
8^0 is greater. As you can see, it is equal to 1, while the other one is equal to 0.01
I'm terrible at explaining stuff. I hope you find this answer somehow helpful :)
To arrange in ascending order means to arrange numbers from the smallest value to the greatest value in the set of numbers provided.
9) 3.021 < 3.12 < 3.121 < 3.21
Look at the 1st decimal place after the point first. 0 is less than 2 & 1, so 3.021 is the least number. Now, for 3.12 & 3.121, look at the 3rd place. 3.12 = 3.120, so it’s smaller than 3.121. Then comes 3.21 which is the greatest number in this set.
10) 5.0090 < 5.05 < 5.059 < 5.5
Here, 5.0090 is the smallest number. Then comes 5.05 = 5.050 which is smaller than 5.059. 5.5 is the greatest number.
_________
RainbowSalt2222 ☔
Answer:
C. 2.8 miles per minute
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
... Tan = Opposite/Adjacent
In the relevant triangle, the side opposite the angle at the observer is the altitude of the airplane, 2 miles. The side adjacent is the horizontal distance to the airplane. At the first observation, that distance (d1) is ...
... tan(40°) = (2 mi)/d1
At the second observation, the horizontal distance to the airplane (d2) is ...
... tan(50°) = (2 mi)/d2
Solving for d1 and d2 and finding the difference (∆d), we have ...
... d1 = (2 mi)/tan(40°)
... d2 = (2 mi)/tan(50°)
... ∆d = d1 -d2 = (2 mi)(1/tan(40°) -1/tan(50°) ≈ 2·(1.1918 -0.8391) mi
... ∆d ≈ 2°0.3526 mi ≈ 0.7053 mi
This distance was flown by the plane in 15 seconds, so it will travel 4 times this distance in 60 seconds (1 minute).
... ∆d/∆t = (0.7053 mi)/(1/4 min) = 4·0.7053 mi/min ≈ 2.8 mi/min
