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Law Incorporation [45]
3 years ago
12

HEEEEEEEEEELPPPPPPPPPPP PLEASE GIVING BRAILIENST TO WHOEVER HELPS ME

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

Same side: 4, 1.5, 5/3, 0.2

Opposite side: -5, -1/4

Step-by-step explanation:

We know that dilation caused by a positive factor leads to the object being on the same side and dilation caused by a negative factor leads to the object being on the opposite side. Therefore, the dilation caused by positive numbers 4, 1.5, 5/3, 0.2 will lead to object being on the same side. And dilation caused by a negative numbers -5 and -1/4 will lead to object being reflected to the opposite side

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To join a Yoga club there is a $100 annual fee and a $5 fee for each class you attend.
Leona [35]

Answer:

210

Step-by-step explanation: so 5 times 12 120 plus 100 is 210

5 0
3 years ago
Please help I'm begging
Elina [12.6K]
The figure is made up of a cone and a cylinder.

Diameter = 16 ft
radius = 16÷2 = 8ft

Volume of the cone = 1/3bh
Volume of the cone = \frac{1}{3}  \pi  r^{2} h
Volume of the cone =  \frac{1}{3} \pi 8^{2}(6) = 402.12

Volume of the cyclinder = bh
Volume of the cylinder = \ \pi r^{2} h
Volume of the cylinder = \ \pi 8^{2}(4) = 1206.37

Total = 402.12 + 1206.37 = 1608.49 cubic feet

6 0
3 years ago
For the data set 2.5, 6.5, 9, 19, 20, 2.5. What is the mean?
Ahat [919]

Answer:

9.9166667

Step-by-step explanation:

All of the numbers equal 59.5 then divide by 6 equals the answer above.

3 0
3 years ago
Is the perpendicular bisector of a line segment also an angle bisector?
algol13

Answer:

yes

Step-by-step explanation:

In an isosceles triangle, one perpendicular bisector is also an angle bisector.

8 0
3 years ago
How do you describe the solution set to a system of linear inequalities?
Tatiana [17]

Answer:

How do you describe the solution set to a system of linear inequalities?

Step-by-step explanation:

The solutions of a system of linear inequalities are all the ordered pairs that make all the inequalities in the system true.

6 0
2 years ago
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