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Mashutka [201]
3 years ago
8

Please HELP I WILL REWARD BRAINLIEST ANSWER IM VERY CONFUSED

Mathematics
1 answer:
ozzi3 years ago
4 0
Dilation is either : enlargement or shirking.

Simply you multiply the ordered pair times the dilation vector (Origin-Centered) 

D.F = dilation factor;


d.f  = 5

C' = d.fC

when you multiply a constant times an ordered pair , it multiples into each of the pair.


C' = 5 ( -5 , 1 ) = ( -25, 5 ) 

In case you were asked for A' , B' (test yourself before checking) 



A' = 5 (-4,3) = ( -20 , 15)

B' = 5 ( 2, 3 ) = ( 10, 15) 

Dividing the dilated by the original pair results in the dilation factor

A'/A =  (-20/15)/(-4,3) = 5(-4,3)/(-4,3) = 5 
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Complete the square to rewrite y = x^2 + 6x + 3 in vertex form. Then state whether the vertex is a maximum or a minimum and give
bixtya [17]

Answer:

Let's complete the square first.

y = x² + 6x + 3

  = (x² + 6x + 9) - 6

  = (x + 3)² - 6

Therefore, the vertex is (-3, -6) and since the coefficient of (x + 3)² is positive, the vertex is a minimum.

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2 years ago
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Explain how to form a linear combination to eliminate the variable y for this system 2x-3y=3 5x+2y=17
Nadusha1986 [10]
 Well to be exact the answer is x=3 y=1
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3 years ago
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cert 22.2 U To 3. Draw an area diagram to find (0.36) (0.53). Label and organize your work so that it can be followed by others.
Masteriza [31]

The result of the product of (0.36) and (0.53) is 0.1908

<h3>How to determine the product</h3>

The product expression is given as:

(0.36) * (0.53)

Rewrite the product as follows:

(0.36) * (0.53) = (0.3 + 0.06) * (0.5 + 0.03)

Expand the product

(0.36) * (0.53) = 0.3 * (0.5 + 0.03)+ 0.06 * (0.5 + 0.03)

Expand

(0.36) * (0.53) = 0.15 + 0.009+ 0.03+ 0.0018

Evaluate the sum

(0.36) * (0.53) = 0.1908

See attachment for the area diagram of the product

Read more about products at:

brainly.com/question/10873737

3 0
1 year ago
Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}

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3 years ago
What is the distance around a triangle that has measuring 2 1/8 feet,3 1/2 feet, 2 1/2 feet
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Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

Hope this will help you!

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2 years ago
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