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Marta_Voda [28]
3 years ago
7

I could use some help please! please

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:

The integers could be 21 and 22

or -22 and -21

Step-by-step explanation:

If two integers are consecutive, then it means that their difference is just 1

if we have the initial value as x , then the other value could be x-1 or x + 1

let us go with x-1

So the product here is;

x(x-1) = 462

x^2-x = 462

x^2 -x -462 = 0

x^2 -22x + 21x - 462 = 0

x(x-22) + 21(x-22) = 0

(x + 21)(x-22) = 0

x = -21 or x = 22

If x = -21

x -1 = -21-1 = -22

if x = 22

x -1 = 22-1 = 21

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Marat540 [252]

Answer:

The location of the new cell phone tower is (h,k) = (3,4), and the equation of the circle is x^{2}+y^{2} -6\cdot x - 8\cdot y = 0.

Step-by-step explanation:

The location of the cell phone tower coincides with the location of a circunference passing through the three cell phone towers. By Analytical Geometry, the equation of the circle is represented by the following general formula:

x^{2} + y^{2}+A\cdot x + B\cdot y +C = 0 (1)

Where:

x - Independent variable.

y - Dependent variable.

A, B, C - Circunference constants.

Given the number of variable, we need the location of three distinct points:

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80 + 8\cdot A + 4\cdot B + C = 0

(x_{3},y_{3}) = (3,9)

90 + 3\cdot A + 9\cdot B + C = 0

Then, we have the following system of linear equations:

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3\cdot A + 9\cdot B + C = -90 (4)

The solution of this system is:

A = -6, B = -8, C = 0

By comparing the general form with the standard form of the equation of the circunference is:

A = -2\cdot h (5)

B = -2\cdot k (6)

C = h^{2}+k^{2}-r^{2} (7)

Where:

h, k - Coordinates of the center of the circle.

r - Radius of the circle.

If we know that A = -6, B = -8 and C = 0, then coordinates of the center of the circle and its radius are, respectively:

h = -\frac{A}{2}

k = -\frac{B}{2}

r = \sqrt{h^{2}+k^{2}-C}

h = 3, k = 4, r = 5

The location of the new cell phone tower is (h,k) = (3,4), and the equation of the circle is x^{2}+y^{2} -6\cdot x - 8\cdot y = 0.

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