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2 years ago

What is the range of y = sin θ ?

2 answers:

7 0

The range of a function is the set of all the possible function outputs. We know that sin theta varies between -1 and 1 if we draw a graph. According to the graph, the largest number that is an output of g is -1, and the smallest number is 1. Every number between them is also an output of g for some input.

=> Therefore, the range of g is [-1,1].

shusha [124]2 years ago

3 0

The answer is<span> [-1,1]. </span>

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Yara multiplies and divides a certain number by the same

Butoxors [25]

For this case we have to:

x: Represents the unknown number

y: Represents the exponent of base 10

So, considering a system of equations we have:

$x * 10 ^ y = 40,000\\\frac {x} {10 ^ y} = 0.000004$

From the first equation we have:

$10 ^ y = \frac {40,000} {x}$

Substituting in the second equation:

$\frac {x} {\frac {40,000} {x}} = 0.000004\\\frac {x ^ 2} {40,000} = 0.000004\\x ^ 2 = 40,000 * 0.000004\\x ^ 2 = 0.16\\x = \pm \sqrt {0.16}$

We choose the positive value:

$x = 0.4$

So, the number is 0.4.

So:

$10 ^ y = \frac {40,000} {0.4}\\10 ^ y = 100,000\\y = 5$

Thus, the exponent is 5.

Answer:

Yara use 0.4 and $10 ^ 5$

8 0

3 years ago

HELP ME PLEASE <br> PLEASE PLEASE PLEASE PLEASE PLEASE

Nimfa-mama [501]

Answer:

19y+5

Step-by-step explanation:

Combine like terms look for all the numbers that have y attached and combine them

7y +12y=19y

Look for terms where nothing is attached it's just the number combine them

6-1=5

Put all together again and you get:

19y+5

8 0

3 years ago

What is the domain and range of f(x)=2.5x when x goes up to 800

Mandarinka [93]

Answer:

Domain: all real numbers. Range: (-∞, 2000]

Step-by-step explanation:

f(x)=2.5x is a simple "ramp" function, a linear function and a polynomial. As such, its domain contains "all real numbers." That value 800 defines the largest value that this f(x) can have: f(800) = 2.5(800) = 2000.

Thus, the range is "all real numbers from -∞ through and including 2000."

3 0

3 years ago

Can someone help me out with number 2?

Norma-Jean [14]

$\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot \frac{ \sqrt{2} }{2}=- \frac{ \sqrt{6} }{4} - \frac{ \sqrt{2} }{4}= -\frac{ \sqrt{6}+\sqrt{2} }{4}$

5 0

3 years ago

How do i find the ratio 2:9

Ganezh [65]

The ratio of 2:9 has to be 2:9 do to the fact you can't simplify the fraction 2/9.
Hoped I helped.

6 0

3 years ago