All categories

3 years ago

Developing Knowledge

Physics

1 answer:

Alla [95]3 years ago

8 0

Answer:

Explanation:

i don't understand what you saying

You might be interested in

you push your little sister on a swing and in 1.6 minutes you make 52 pushes what is the frequency of your swing? answer in unit

ehidna [41]

<span> If you make 46 pushes then your sister swings through 46 cycles and she does so in 90 seconds. The frequency would be 46/90 = 0.511 Hz.</span>

6 0

3 years ago

What happens when an electron moving from the 3rd energy level to the 1st energy level?

Sholpan [36]

Answer:

A photon of wavelength 103 nm is released

Explanation:

When an electron in an atom jumps from a higher energy level to a lower energy level, it releases a photon whose energy is equal to the difference in energy between the two levels.

For example, if we are talking about a hydrogen atom, the energy of the levels are:

$E_1 = -13.6 eV\\E_2 = -3.4 eV\\E_3 = -1.5 eV$

So, the energy of the photon released when the electron jumps from the level n=3 to n=1 is

$\Delta E = E_3 - E_1 = -1.5 -(-13.6)=12.1 eV$

In Joules,

$\Delta E =12.1\cdot 1.6\cdot 10^{-19} = 1.94\cdot 10^{-18} J$

We can also find the wavelength of this photon, using the equation:

$\Delta E = \frac{hc}{\lambda}\rightarrow \lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{1.94\cdot 10^{-18}}=1.03\cdot 10^{-7} m = 103 nm$

7 0

4 years ago

a 4.60 kg mass is placed on top of a vertical spring, which compresses a distance of 2.31 cm. calculate the force constant (in n

Lerok [7]

The restoring force of the spring cancels the weight of the mass, so by Newton's second law

∑ F = F[spring] - mg = 0 ⇒ F[spring] ≈ 45.1 N

where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,

F[spring] = k x

where x = 0.0231 m. Then the spring constant is

k = F[spring]/x ≈ 1950 N/m

4 0

3 years ago

An electric circuit whose components are connected by separate conducting paths

nadya68 [22]

I would help if i could im sorry im sure someone else will answer soon

3 0

3 years ago

Calculate the power produced by a 12 V battery charger if it delivers:A. 10 A in the fast charge modeB. 2 A in trickle charge mo

Novay_Z [31]

The electric power (P) produced by an electric current (I) passing through a voltage (V) is given by the equation:

$P=VI$

If the battery charger works with a voltage of 12V, replace V = 12V into the equation, as well as the corresponding values for the electric current to find the power produced in each case.

A) I = 10A

Replace V=12V and I=10A to find the power produced in the fast charge mode:

$P=(12V)(10A)=120W$

B) Replace V=12V and I=2A to find the power produced in the trickle charge mode:

$P=(12V)(2A)=24W$

Therefore, the power produced by a 12V battery charger is equal to 120 Watts when it delivers 10A in fast charge mode, and 24 Watts when it delivers 2A in trickle charge mode.

3 0

1 year ago