Question

Se suelta una piedra cerca de la superficie lunar y cae libremente durante 7 segundos. La aceleración de la gravedad lunar es de 1,6 m/s² ¿qué velocidad alcanzará?

Answer 1

Answer:

v = 11.2 m/s

Explanation:

A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?

Given that,

The acceleration due to the gravity of lunar gravity is 1.6 m/s²

A stone is dropped near the lunar surface and falls freely for 7 seconds.

We need to find the speed with which it reach.

The initial velocity of the stone will be 0 as it was at rest.

Using equation of kinematics v=u+at

$v=1.6\times 7\\\\v=11.2\ m/s$

So, the stone will reach with a speed of 11.2 m/s