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3 years ago

What is the mass of an asteroid with a speed of 200 m/s and a momentum of 2,000 kg m/s?

Physics

2 answers:

Bezzdna [24]3 years ago

4 0

Answer:10 kg

Explanation: momentum p = mv and m = p/v

Mass m = 2000 kgm/ s / 200 m/s

r-ruslan [8.4K]3 years ago

3 0

Answer:

jhnnmhunn vgu fhbiy f

Explanation:

hjbgyvfvubhjgvg

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A bullet moving at a speed of 152 m/s passes through a plank of wood at 128m/s. Another bullet moving at 97m/s passes through th

Ivahew [28]

Answer:

The speed of the plank is 81.68 m/s

Explanation:

Given that,

Speed of bullet = 152 m/s

Speed of wood = 128 m/s

Speed of another bullet = 97 m/s

We need to calculate the speed of plank

Using conservation of momentum

$m_{1}u_{1}=(m_{1}+m_{2})v$

Where,

u = initial velocity

v = final velocity

$152m_{1}=(m_{1}+m_{2})128$ ....(I)

$m_{1}97=(m_{1}+m_{2})v$ ....(II)

From equation(I) and equation(II)

$\dfrac{152}{97}=\dfrac{128}{v}$

$= \dfrac{128\times97}{152}$

$v=81.68\ m/s$

Hence, The speed of the plank is 81.68 m/s

4 0

3 years ago

A student wants to determine the speed of sound at an elevation of one mile. To do this the student performs an experiment to de

Lorico [155]

Answer:

The correct answer is a

Explanation:

The speed of a sound wave depends on the square root of the modulus of compressibility and the density of the medium.

For the same medium, the speed of sound depends on the temperature of the fora

v = $v_o \ \sqrt{1 + \frac{T}{273} }$

Therefore, the different results that are obtained are due to changes in temperature. The correct answer is a

since this way it has the values of the speed of sound for each temperature, for which it can compare with the results obtained from the trip.

3 0

3 years ago

You throw a baseball directly upward at time t = 0 at an initial speed of 12.3 m/s. What is the maximum height the ball reaches

Semmy [17]

Explanation:

At the maximum height, the ball's velocity is 0.

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (12.3 m/s)² + 2(-9.80 m/s²)(x - 0 m)

x = 7.72 m

The ball reaches a maximum height of 7.72 m.

The times where the ball passes through half that height is:

x = x₀ + v₀ t + ½ at²

(7.72 m / 2) = (0 m) + (12.3 m/s) t + ½ (-9.8 m/s²) t²

3.86 = 12.3 t - 4.9 t²

4.9 t² - 12.3 t + 3.86 = 0

Using quadratic formula:

t = [ -b ± √(b² - 4ac) ] / 2a

t = [ 12.3 ± √(12.3² - 4(4.9)(3.86)) ] / 9.8

t = 0.368, 2.14

The ball reaches half the maximum height after 0.368 seconds and after 2.14 seconds.

5 0

4 years ago

Hey help me and thanks in advance if you do

blsea [12.9K]

P = W / t

2000 = 30000 / t

t = 30000/2000

t = 30/2

t = 15 seconds

3 0

3 years ago

Read 2 more answers

Does the horizontal motion of the projectile depend on the vertical motion?

bezimeni [28]

No, resolve in both directions separately

4 0

3 years ago

Read 2 more answers