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IRINA_888 [86]
3 years ago
5

If Whitney wrote the decimal representations for the first 300 positive integer multiples of 5 and did not write any other numbe

rs, how many times would she have written the digit 5
Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

201 times

Step-by-step explanation:

Since it's the first 300 positive integer multiples of 5, then the last integer will be: 300 × 5 = 1500

While the first is 5.

The sequence is like this;

5, 10, 15, 20, 25, 30, 35, .. 1500

Since for every 2 integers that are multiples of 5, 1 will include the digit 5, then it means that, number of times the unit place will have 5 is; 300/5 = 150 times

Now, between 5 and 100, the only value that has 5 in it's tense place is 50 & 55.

So for every 100 numbers, we have 2 times to write 5 in the tens place. Thus, for 1500 numbers, we will write 5 in the tens place: 1500/100 × 2 = 30 times

Now, for the hundreds place, from 500 and 600, we have 21 multiples of 5 inclusive of 500 and 600 but since we want the one that has 5 in the hundreds place, then it is 20 as they all start with 5 excluding 600.

Also, from 1000 to 1500, the only number that has 5 in its hundreds place is 1500.

Thus,total times 5 is written in the hundreds place = 21 times

Total number of times 5 is written = 150 + 30 + 21 = 201 times

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when x = -1,  y = -3

when x = -1,  y = -1

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Step-by-step explanation:

x = -1;  plug in y = 2(-1) - 1 = -2 - 1 = -3

x = 0;  plug in y = 2(0) - 1 = 0 - 1 = -1

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3 years ago
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6 0
3 years ago
A patient with end-stage kidney disease has nine family members who are potential kidney donors. How many possible orders are th
eduard

Answer: 504

Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

Formula for permutation:  ^nP_r=\dfrac{n!}{(n-r)!}

Given : The number of family members who are potential kidney donors. = 9

Number of people needed to be selected for best match, a second-best match, and a third-best match ( in an order)=3

Then, the number of possible orders are = ^9P_3=\dfrac{9!}{(9-3)!}

=\dfrac{9\times8\times7\times6!}{6!}=504

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3 years ago
A cube made of an unknown material has a height of 9 cm. The mass of this cube is 3.645 grams. What is the density of this cube?
ehidna [41]

Answer:

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volume = 9×9×9

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density = 3.645/729

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the volume is 729 cm³ cause the given height is 9cm and it is a cube. cube has equal sides so their lengths are the same.

volume = length × height × width

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