The area of a rectangular garden is given by the trinomial x^2+6x-27. what are the possible dimensions of the rectangle? use fac

Question

3 years ago

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toring

2 answers:

snow_tiger [21] · Answer 1 · 2022-04-19T01:10:17+03:00

6 0

A = x^2 + 6x - 27 A = x^2 + 9x - 3x - 27 A = x(x+9)-3(x+9) A = (x+9)(x-3) A = lw l = (x+9) w =(x-3)

nikitadnepr [17] · Answer 2 · 2022-04-19T03:05:07+03:00

Answer:

Step-by-step explanation:

Given that a garden is in rectangular form

Area of the garden = $x^2+6x-27$

We know that area of a rectangle = length x width

Hence length x width = $x^2+6x-27$

There can be infinite number of answers for this equation.

Let us assume that both length and width are rational.

Then the factors would be answers.

Factorise

$x^2+6x-27$ as

$(x+9)(x-3)$

Since normally length would be longer, we can say

length = x+9 and width = x-3, for x >3.