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neonofarm [45]
3 years ago
14

The area of a rectangular garden is given by the trinomial x^2+6x-27. what are the possible dimensions of the rectangle? use fac

toring
Mathematics
2 answers:
snow_tiger [21]3 years ago
6 0
A = x^2 + 6x - 27 A = x^2 + 9x - 3x - 27 A = x(x+9)-3(x+9) A = (x+9)(x-3) A = lw l = (x+9) w =(x-3)
nikitadnepr [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that a garden is in rectangular form

Area of the garden = x^2+6x-27

We know that area of a rectangle = length x width

Hence length x width = x^2+6x-27

There can be infinite number of answers for this equation.

Let us assume that both length and width are rational.

Then the factors would be answers.

Factorise

x^2+6x-27 as

(x+9)(x-3)

Since normally length would be longer, we can say

length = x+9 and width = x-3, for x >3.

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Write This number in expanded form 719,927
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Seven hundred nine thousand and nine hundred twenty seven
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Triangle A has side lengths of 10 units, 24, units, and 26 units. Ryan cut out 2 copies of triangle A and joined them together t
sergejj [24]

Answer:

Perimeter of Rectangle will be 68 units.

Step-by-step explanation:

Given:

Length of side 1 = 10 units

Length of side 2 = 24 units

Length of side 3 = 26 units

Now we will check whether the triangle A is right angle triangle or not;

(Length of side 3)^{2} = 26^2 = 676

(Length of side 2)^{2} = 24^2 = 576

(Length of side 1)^{2} = 10^2 = 100

Now From above we can see that;

676 = 576 + 100

Hence we can say ;

(Length of side 3)^{2} = ](Length of side 2)^{2} + (Length of side 1)^{2}

By Converse of Pythagoras theorem.

"Hence When the square of the length of the hypotenuse is equal to sum of the square of other two sides we can say that triangle is a right angled triangle."

Now Given:

Ryan cut out 2 copies of triangle A and joined them together to form a rectangle.

So we can say that the hypotenuse side of the triangle will become diagonal of the rectangle and other two side will become length and width.

Now;

Length of rectangle = 24 units

Width of rectangle = 10 units.

We need to find the perimeter of rectangle.

Now Perimeter of rectangle is 2 times sum of Length and width.

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Perimeter of rectangle = 2(l+w) = 2\times (24+10) = 2\times 34 =68 units.

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4 0
3 years ago
The digit 5 appears twice in the number 255,120. How does the total value of the 5 on the right compare to the total value of th
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Answer:

The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.

Step-by-step explanation:

What gives the number "255,\!120" its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first \verb!5! to \verb!6! would give 2\mathbf{6}5,\!120 and increase the value of this number by 10,\!000. On the other hand, changing the second \verb!5!\! to \verb!6!\! would give 25\mathbf{6},\!120, which is an increase of only 1,\!000 compared to the original number.

The order of these two digits matter because the number "255,\!120" is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in 255,\!120\!:

\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}.

(Note that the index starts at 0 from the right-hand side.)

Using these weights, the value 255,\!120 can be written as the sum:

\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}.

As seen in this sum, the first "5" contributed 50,\!000 to the total value, while the second "5\!" contributed only 5,\!000.

Hence: The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.  

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