The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago

What is the solution of this equation? 3a = 18

Triss [41]

3a =18

3a/3 = 18/3

a = 18/3

a = 6

Hope this helps

6 0

4 years ago

Read 2 more answers

Please graph y= 1/2x–3 Please i need help with this <3

erik [133]

Answer:

coordinates are 6, -3

Step-by-step explanation:

When it's plotted out onto a graph, the answer comes down to 6, -3 (also remember, it's X then Y)

6 0

3 years ago

HELP ME PLEASEEEE I BEG YOUUU

Alex777 [14]

Answer:

1.a. E>D

b. E<F

2. Yes. There are multiple combinations on how to do number 1. The first question asks how for a, you need a letter that is bigger than another letter, and for b, you need a letter that is smaller than the other letter's value. There are many ways to go about that previous problem.

Step-by-step explanation:

Hello!

To solve this question, we first need to realize that this is a simple number line. A number line is just a line that contains multiple points from the left being negative, middle is zero, and right becoming increasingly positive.

In this case, D is zero, and A-C are deemed negative. E-F are positive.

For a, we need to find a point that is bigger than another point.

We have various answers for this. F is bigger than A-E, E is bigger than A-D, D is bigger than A-C, C is bigger than A-B, and B is bigger than A. As long as any of your answer goes along this format it is correct.

B is asking a number that is smaller than that said number. A is smaller to B-F, B is smaller to C-F, C is smaller to D-F, E is smaller to F. So again, any letter combination that falls within this category is correct.

For the last one, there are multiple combinations, meaning there is just not one answer that fulfills that question.

6 0

2 years ago