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s2008m [1.1K]
3 years ago
14

I've never even seen a box and whiskers plot before!! Should be pretty straight forward though. Thanks!

Mathematics
2 answers:
dybincka [34]3 years ago
8 0
So a box and whiskers plot is relatively simple if you know how to do it.

The left whisker ending, which is at 35, signifies the minimum.

The right whisker ending, which is at 99, signifies the maximum.

The middle line, at 68, is the median.

And the edge of the box on the left, at 50, is the First Quartile. (If you don't know what that is, basically the marker in between the first quarter and the second quarter)

And the edge of the box on the right is the Third Quartile, (Same thing except in between the third quarter and fourth)

So since the question is asking how many students scored better than an 85, and we know that 85 is the third quartile here, we know that 1/4 of the students scored better than an 85.

(So basically each section is 1/4 of the data set)

And 1/4 of 24 is 6.

So 6 students scored better than an 85.
alisha [4.7K]3 years ago
7 0
For a box and whispers plot, each section represents 25% of the data. Therefore, the area from 85-99 represents 25% of the data.

25% of 24 students= 6 students
Final answer: 6 students
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He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. which best
seropon [69]

The question is incomplete. Completed question is given below the answer.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Given  

Then the solution follows thus:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

It can be seen that his solution is correct. But 6 is not an extraneous solution.

An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.

When 6 is substituted into the original equation, the original equation holds.

Therefore, his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Learn more about extraneous solution here: brainly.com/question/3751209

#SPJ4

Completed question:-

A student solves the following equation for all possible values of x:His solution is as follows:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.

Which best describes the reasonableness of the student’s solution?

His solution for x is correct and his explanation of the extraneous solution is reasonable.

His solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

His solution for x is incorrect. When solved correctly, there are no extraneous solutions.

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1 negative startroot 2 end root 1 start root 2 end root
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Number 3 (show work) :))
WINSTONCH [101]

(DVD player+ TV)=   49.36+705.20= 754.56

754.56/12=62.88

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