To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
132, to sum up, the Lcm Of 11 and 12 is 132
1. 47
2. 70.4 ft per min
3. 13.33333333333333
Answer:
158 square feet
Step-by-step explanation:
2(lb+bh+lh)
2(40+24+15)
80+ 48+30
158
The given function is
The general form of the cosine function is
a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is
The equation of the midline is
Since the maximum is at the greatest value of cos, which is 1, then
Since the minimum is at the smallest value of cos, which is -1, then
Then substitute them in the equation of the midline
The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3
