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STALIN [3.7K]
3 years ago
12

What is the overlap of Data Set 1 and Data Set 2?

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

its corresponding to the wrong one

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the function t(n) 8n represents the number of tires t(n) that are needed for n trucks. if t(n)=200. what is the value of n?
mr_godi [17]

Step-by-step explanation:

if I understand correctly, then the function is

t(x) = 8x

now we know, that for a specific n

t(n) = 200

that means

200 = 8n

n = 200/8 = 25

the function tells us, that for 25 trucks we need 200 tires.

8 0
2 years ago
For the problem below, θ is a central angle in a circle of a radius r. Find the length of arc s cut off by θ.
mixas84 [53]

Answer:

Here, we will use the formula from trigonometry which defines a radian

we know that an angle is a radian when the length of the radius of the circle is equal to the length of the arc formed

hence, if the radius is r and the arc is r, the angle (in radians) will be 1

if the radius is r and the arc is 2r, the angle in radians will be equal to:

length of arc / radius = 2r/r = 2 radians

I believe this will explain what is actually happening in these type of questions

So, the equation:

Θ(in radians) = s / r (where the length of arc is s and the radius is r)

π/4 = s / 12

s = 3π or 9.42 inches

4 0
3 years ago
What is the equation in slope-intercept form of the line that passes through the points (2,-3)
Fittoniya [83]

Answer:

y=1x-6

Step-by-step explanation:

luckily i love math, plz put as brainliest

6 0
3 years ago
HELP HELP!!
Goryan [66]

Answer:

0

Step-by-step explanation:

p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}

7 0
3 years ago
The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is
qwelly [4]

Answer:

(C)72.4 in

Step-by-step explanation:

Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.

Consider the attached diagram

AB=BC=x

However to be able to solve for x, we form a right triangle with endpoints A and C.

Since the hypotenuse is always the longest side in a right triangle

Hypotenuse, AC=30 Inches

Using Pythagoras Theorem

30^2=x^2+x^2\\900=2x^2\\x^2=450\\x=\sqrt{450}\\x=21.21$ inches

Therefore, the smallest possible perimeter of the triangle

Perimeter=2x+30

=2(21.21)+30

=42.42+30

=72.4 Inches (rounded to the nearest tenth)

4 0
3 years ago
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