Answer:
D
Step-by-step explanation:
12x - 13 = -6x + 17
12x+6x=17+13
18x=30
X= 30÷18
X= 1.66667
Answer:
Area required for circular hot tube = 6,218 inch² (Approx.)
Step-by-step explanation:
Given:
Diameter of circular hot tube = 89 inches
Value of π = 3.14
Find:
Area required for circular hot tube
Computation:
Radius of hot tube = Diameter / 2
Radius of hot tube = 89 / 2 inches
Area required for circular hot tube = Area of circle
Area of circle = πr²
Area required for circular hot tube = πr²
Area required for circular hot tube = (3.14)(89/2)²
Area required for circular hot tube = (3.14)(7921 / 4)
Area required for circular hot tube = (3.14)(1,980.25)
Area required for circular hot tube = 6,217.985
Area required for circular hot tube = 6,218 inch² (Approx.)
Start with #47. To find the critical values, you must differentiate this function. x times (4-x)^3 is a product, so use the product rule. The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x]
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of f '(x) = (4-x)^2 [-3x+4-x]. (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1. Thus, the "cv" are {4,1}.
Evaluate the given function at x: {4,1}. For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8. Thus, one of the extreme values is (1,8).
Answer:
3.3 kg
Step-by-step explanation:
1 pound = 0.453592kilogram
so you just need to 7.3*0.453592= 3.3kilograms
