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marshall27 [118]

3 years ago

9

Jane used $68 more than two-fifths of her last paycheck to purchase a new surfboard. If the surfboard cost $289, find the amount

of her paycheck

1 answer:

garri49 [273]3 years ago

4 0

Answer:

552.5

Step-by-step explanation:

2/5x + 68 = 289

2/5 x = 289 - 68

2/5x = 221

x = 221 * 5/2 = 552.5

I hope im right!!!

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How do I solve this????

Arlecino [84]

Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so $\bf \begin{cases}
a+b=22\\
--------------\\
\boxed{b}=5a+4\qquad thus\\
--------------\\
a+\boxed{5a+4}=22
\end{cases}$

solve for "a", to see what the smaller one is

what's "b"? well, b = 5a + 4

3 0

3 years ago

Can someone please help me!

Alexeev081 [22]

Answer:

7)no

Step-by-step explanation:

When you plug in the numbers

3(2)-0=-6

6-0=6

6 does not = -6

5 0

3 years ago

-2x = 16–8y<br> x+4y= 25<br> Solve by substitution

ra1l [238]

Answer:

( $\frac{17}{2}$ , $\frac{33}{8}$

Step-by-step explanation:

Given the 2 equations

- 2x = 16 - 8y → (1)

x + 4y = 25 → (2)

Rearrange (2) expressing x in terms of y by subtracting 4y from both sides

x = 25 - 4y → (3)

Substitute x = 25 - 4y into (1)

- 2 (25 - 4y) = 16 - 8y ← distribute left side

- 50 + 8y = 16 - 8y ( add 8y to both sides )

- 50 + 16y = 16 ( add 50 to both sides )

16y = 66 ( divide both sides by 16 )

y = $\frac{66}{16}$ = $\frac{33}{8}$

Substitute this value into (3) for corresponding value of x

x = 25 - 4 × $\frac{33}{8}$ )

= $\frac{50}{2}$ - $\frac{33}{2}$ = $\frac{17}{2}$

Solution is ( $\frac{17}{2}$ , $\frac{33}{8}$ )

5 0

3 years ago

Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)

Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

$m =\frac{y_{2}-y_{1} }{x_{2} -x_{1} } =\frac{-7-5}{2-(-1)} = \frac{-12}{3} = -4$

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

$y - y_{1} = m( x-x_{1} )$

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em> </em></u>

6 0

3 years ago

Which of the following is NOT a linear factor of the polynomial function?

Natalija [7]

Answer:

Among the four choices, $(x + 5)$ is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let $a$ denote some constant. A linear factor of the form $(x - a)$ is a factor of a polynomial $f(x)$ if and only if $f(a) = 0$ (that is: replacing all $x$ in the polynomial $f(x) \!$ with the constant $a\!$ would give this polynomial a value of $0$ .)

For example, in the second linear factor $(x - 2)$ , the value of the constant is $a = 2$ . Verify that the value of $f(2)$ is indeed $0$ . (In other words, replacing all $x$ in the polynomial $f(x) \!$ with the constant $2$ should give this polynomial a value of $0\!$ .)

$\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}$ .

Hence, $(x - 2)$ is indeed a linear factor of polynomial $f(x)$ .

Similarly, it could be verified that $(x - 5)$ and $(x + 2)$ are also linear factors of this polynomial function.

Rewrite the first linear factor $(x + 5)$ in the form $(x - a)$ for some constant $a$ : $(x + 5) = (x - (-5))$ , where $a = -5$ .

Calculate the value of $f(5)$ .

$\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}$ .

$f(5) \ne 0$ implies that $(x - (-5))$ (which is equivalent to $(x + 5)$ ) isn't a linear factor of this polynomial function.

3 0

3 years ago