Answer:
Step-by-step explanation:
We have given:
√2x+3 - √x+1 = 1
First of all isolate the square root of the left hand side:
√2x+3 = √x+1 +1
Now take square on both sides.
(√2x+3)^2 = (√x+1 +1)^2
Open the R.H.S by squaring formula.
∴(a+b)^2 = a^2+2ab+b^2
2x+3 = (√x+1)^2 + 2(√x+1)(1)+(1)^2
2x+3 = x+1 +2√x+1 +1
2x+3 = x+2 +2√x+1
Combine the like terms:
2x-x+3-2 = 2√x+1
x+1 = 2√x+1
Take square on both sides
(x+1)^2 = (2√x+1)^2
x²+2x+1 = 4x+4
x²+2x-4x+1-4 = 0
x²-2x-3 = 0
Now solve the quadratic equation:
a = 1 , b= -2 , c = -3
x = -b+/-√b²-4ac/2a
x = -(-2)+/-√(-2)² - 4(1)(-3) / 2(1)
x = 2 +/- √4+12 / 2
x = 2+/- √16/2
x = 2+/- 4 /2
x = 2+4/2 , x = 2-4/2
x = 6/2 , x = -2/2
x = 3 , x = -1
The solutions we get is (3, -1).
1. x² - 6x + 8
4*2 equals 8 and if you add 4 and 2 it gives you 6
-4-2= -6
=(x-4)(x-2)
3. the answer is A
if you plug in the points into the equation y=x
y= 1/2x + 4
given point: (4,6) x=4 y=6
6= 1/2(4)+4
6=6
Multiply both 1/6=11/66, 3/11=9/66. 1/6 is bigger.
Just reverse search this on google
