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3 years ago

Algebra II:

Mathematics

2 answers:

pickupchik [31]3 years ago

7 0

Answer:

Step-by-step explanation:

geometric sequence is given as Tn=ar^n-1

where Tn is the last term,a is the first term, r is the common ratio, n is the nth term

hence 48=a2^(4-1)

48=a2^3

48=a8 (divide both by 8 to ramain with a)

6=a

therefore the first term is 6 .

exis [7]3 years ago

3 0

Answer:

Step-by-step explanation:

$nth \: term \: of \: geometric \: \\ sequence \: is \: given \: as : \\ a_n = a {r}^{n - 1} \\ (a = ?, \: \: r = 2)\\ \\ a_4 =48......(given) \\ \\ \therefore \: a {(2)}^{4 - 1} = 48 \\ \\ \therefore \: a {(2)}^{3} = 48\\ \\ \therefore \: 8a = 48 \\ \\ \therefore \: a = \frac{48}{8} \\ \\ \therefore \:a = 6$

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The amount of time the husband and the wife spend on house work is measured for 15 women and their 15 husbands. For the wives th

dolphi86 [110]

Answer:

The value of the test statistic is z = -0.877.

Step-by-step explanation:

Testing the difference in mean time spent on housework between husbands and wives.

At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:

$H_0: \mu_H - \mu_W = 0$

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.

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In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.

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