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rodikova [14]
3 years ago
14

Algebra II:

Mathematics
2 answers:
pickupchik [31]3 years ago
7 0

Answer:

6

Step-by-step explanation:

geometric sequence is given as Tn=ar^n-1

where Tn is the last term,a is the first term, r is the common ratio, n is the nth term

hence 48=a2^(4-1)

48=a2^3

48=a8 (divide both by 8 to ramain with a)

6=a

therefore the first term is 6 .

exis [7]3 years ago
3 0

Answer:

6

Step-by-step explanation:

nth \: term \: of \: geometric \:  \\ sequence \: is \: given \: as :  \\ a_n = a {r}^{n - 1}  \\ (a = ?, \:  \: r = 2)\\  \\ a_4 =48......(given)  \\  \\  \therefore \: a {(2)}^{4 - 1}  = 48 \\  \\ \therefore \: a {(2)}^{3}  = 48\\  \\ \therefore \: 8a   = 48 \\  \\ \therefore \: a   =  \frac{48}{8}  \\  \\ \therefore \:a = 6

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