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nadezda [96]
2 years ago
12

Please help me with this

Mathematics
2 answers:
nekit [7.7K]2 years ago
6 0

Answer:

7/8 . 6/7

9/10 . 5/6

Step-by-step explanation:

B and C or you could say 2 and 3 are the right ones

pentagon [3]2 years ago
5 0
1/2x1/2 = 0.25
7/8 x 6/7 = 0.75
9/10 x5/6 = 0.75
3/4x 3/4 = 0.5625
1/4 x 1/2 = 0.125
So its B and C because 0.75 as a fraction is 3/4!
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Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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And p is the probability of X happening.

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Find the probability that between 4 and 6 (including endpoints) have a laptop.

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157

P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815

P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

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