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melomori [17]
3 years ago
14

Find the value of x.

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
Please take another picture with the full question. I cannot help you with your question if not everything is presented.
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A.118<br> B.242<br> C.180<br> D.149
Scrat [10]

Answer:

Step-by-step explanation: First find angle 2. 180-59= 121 angle 1 and 2 are equal so their sum must be

242

5 0
3 years ago
HELP !! anyone please i need this done in less than in hour JUST ANSWERS WILL DO
MrRa [10]

Answer:

Step-by-step explanation:

4 0
2 years ago
I need c and d answered badly
Kisachek [45]

C. translated down 2 units

---The "-2" located on the outside of f(x) tells us that the y-values are being changed. With that, the graph can be moved up or down. The presence of the negative/subtraction sign tells us that the graph is moved down.

D. translated right 4 units

---The "-4" located with the x in f(x) tells us that the x-values are being changed. The only tricky thing about this is that the direction of the movement is actually the opposite of the sign. So with the negative/subtraction sign, the graph is moved to the right instead of the left.

Hope this helps!

3 0
2 years ago
1. If we have 3 babies what is the probability they’re going to be all boys?
adelina 88 [10]
I don’t knowww mannnnnn
5 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
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