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Alex Ar [27]
3 years ago
9

A shark was caught whose tail weighed 200 pounds. The head of the shark weighed as much as its tail plus half its body. It’s bod

y weighed as much as its head and tail. What is the weight if the shark?
Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:1600

Step-by-step explanation:To solve this problem, we’ll have 3 variables

T for weight of tail

H for weight of head

B for weight of body

We know that T = 200 pounds

The head of the shark is the weight of the tail + half the body. Therefore, we can use the formula:

H = T + 0.5B

The body weighs as much as the head and tail. That will be

B = H + T

We can substitute H + T in the place of B in the H equation, so we get

H = T + 0.5H + 0.5T

Combining like terms, we get: 0.5H = 1.5T

Because T = 200 pounds, we can say 0.5H = 1.5 * 200, which simplifies to 0.5H = 300

Divide both sides by 0.5 and get H = 600 pounds

We can then find the weight of the body to be H + T, which is 200 + 600, and that adds up to 800 pounds

The total weight of the body is B + H + T, which equals 200 + 600 + 800, which is 1600 pounds.

kobusy [5.1K]3 years ago
6 0

Answer: Lets denote:

Tail by T

Head by H

and Body by B

Given info:

Statement 1: Head weighs as much as the tail plus half of it’s body

H =T + 1/2B

Thus,

H = 200 + 1/2 B …. Equation 1

Statement 2: Body weighs as much as head and tail.

B = H + T

B = H + 200 …. Equation 2

substituting value of B from equation 2 into 1.

H = 200 + 1/2H + 100

1/2H = 300

H = 600

B = 800

Shark’s weight = (H+T+ B) = 1600 pounds

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