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Vsevolod [243]
2 years ago
8

HELP ME PLS TYYYYY .

Mathematics
1 answer:
Masteriza [31]2 years ago
4 0

Answer:

A (5,-4)

Step-by-step explanation:

I hope this helps answer your question(s). Please mark brainliest.

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Pls help me do this math homework. <br>Thanks you
Dmitriy789 [7]
80,236

a) the digit 8 is in the ten thousands place.
The value of this digit is 80,000.

b) the digit 6 is in the ones place.
The value of this digit is 6.

c) the digit in the thousands place is 0.
7 0
3 years ago
What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1
Mrrafil [7]
A horizontal asymptote of a function f(x) is given by y = lim f(x) as x --> ∞ and x --> –∞. In this case, 
\lim_{x \to \infty}  \frac{-2x}{x+1} = \lim_{x \to \infty}  \frac{-2x}{x(1+ \frac{1}{x} )}\\&#10;=\lim_{x \to \infty}  \frac{-2}{1+ \frac{1}{x} }\\&#10;= -2&#10;

Thus, the horizontal asymptote of f(x) is y = –2.
7 0
3 years ago
Read 2 more answers
Parcc chapter 7 pythagorean theorem
Bumek [7]
So, we know that a^2 + b^2 = c^2.  Right?  That is called the Pythagorean Theorem.

In this case.  We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b.  a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c.  We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.



7 0
3 years ago
Thom worked 20 hours last week at the sporting-goods store and earned
Ilia_Sergeevich [38]

Answer:

He must work additional 8 hours.

Step-by-step explanation:

Because 1550.00/20=7.75

217.00/7.75=28

28-20=8

So,an additional of 8 hours

6 0
3 years ago
Statements :
3241004551 [841]

Answer:

"e^x is irrational for every nonzero integer x"

Step-by-step explanation:

The original statement is

"e^x is rational for some nonzero integer x."

The negation is technically:

"It is NOT true that e^x is rational for some nonzero integer x."

So it's expressing that it's false that e^x can be rational for some nonzero integer x.

This just means that e^x is always irrational when x is a nonzero integer.

Which can be worded as

"e^x is irrational for every nonzero integer x"

4 0
3 years ago
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