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Anarel [89]
2 years ago
14

help me please annotate it or something!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Flauer [41]2 years ago
4 0

Answer:

Step-by-step explanation:

c

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gladu [14]
Of course! 2 of the square root of six is roughly 4.89, rounded up being 5.
3 0
3 years ago
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HELP I WILL GIVE BRAINLIEST
Maksim231197 [3]

Answer: D

Step-by-step explanation:

-4 < -w

w > -4

Since it doesn't have an equal sign, its an open circle. Since its greater than -4, it is going to the right, so shade right.

Answer is D

3 0
3 years ago
A rancher has 200 feet of fencing to enclose two adjacent corrals
Arturiano [62]

Answer:

a) Each corral should be 33⅓ ft long and 25 ft wide

b) The total enclosed area is 1666⅔ ft²

Step-by-step explanation:

I assume that the corrals have identical dimensions and are to be fenced as in the diagram below

Let x = one dimension of a corral

and y = the other dimension

 

(a) Dimensions to maximize the area

The total length of fencing used is:

4x + 3y = 200

4x = 200 – 3y

x = 50 - ¾y

The area of one corral is A = xy, so the area of the two corrals is

A = 2xy

Substitute the value of x

A = 2(50 - ¾y)y

A = 100 y – (³/₂)y²

This is the equation for a downward-pointing parabola:

A = (-³/₂)y² + 100y

a = -³/₂; b = 100; c = 0

The vertex (maximum) occurs at  

y = -b/(2a)  = 100 ÷ (2׳/₂) = 100 ÷ 3 = 33⅓ ft  

4x + 3y = 100

Substitute the value of y

4x + 3(33⅓) = 200

4x + 100 = 200

4x = 100  

x = 25 ft

Each corral should measure 33⅓ ft long and 25 ft wide.

Step 2. Calculate the total enclosed area

The enclosed area is 50 ft long and 33⅓ ft wide.

A = lw = 50 × 100/3 = 5000/3 = 1666⅔ ft²

6 0
3 years ago
Me need help math';;''';';';'
QveST [7]

Answer:

Adjacent angles

Step-by-step explanation:

They share a common vertex and side, fulfilling the criteria that makes them adjacent angles.

Sorry, needed to make up characters lol.

3 0
2 years ago
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Aiden borrows a book from a public library. He read a few pages on day one. On day two, he reads twice the number of pages than
Fofino [41]

Let the number of pages read on day 1 be = x

Then on day 2 he read twice the pages from day one, it is = 2x

On 3rd day he read 6 pages less than 1st day, it is = x-6

Total pages are = 458

The equation becomes: x+2x+x-6=458

4x-6=458

4x=464

x=116

So on the third day, Aiden read x-6=116-6=110 pages.

5 0
3 years ago
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